Knot Groups and Slice Conditions
نویسنده
چکیده
We introduce the notions of “k-connected-slice” and “π1-slice”, interpolating between “homotopy ribbon” and “slice”. We show that every high-dimensional knot group π is the group of an (n− 1)-connected-slice n-knot for all n ≥ 3. However if π is the group of an n-connected-slice n-knot the augmentation ideal I(π) must have deficiency 1 as a module. If moreover n = 2 and π is finitely generated then π is free. In this case def(π) = 1 also. An n-knot is a locally flat embedding K : S → S. Such a knot K is homotopy ribbon if it is a slice knot with a slice disc whose exterior W has a handlebody decomposition consisting of 0-, 1and 2-handles. The dual decomposition of W relative to ∂W has only (n+1)-, (n+ 2)and (n+3)-handles, and so the inclusion of ∂W into W is n-connected. More generally, we shall say that K is k-connectedslice if there is a slice disc with exterior W such that (W, ∂W ) is kconnected, and that K is π1-slice if the inclusion of the knot exterior X(K) = Sn+2 −K(Sn)×D2 into the exterior of some slice disc induces an isomorphism on fundamental groups. Every ribbon knot is homotopy ribbon [4], while if n ≥ 2 “homotopy ribbon” ⇒ “n-connected-slice” ⇒ “π1-slice” ⇒ “slice”. Nontrivial classical knots are never π1-slice, since the longitude of a slice knot is nullhomotopic in the exterior of a slice disc. (A 1-knot is “homotopically ribbon” in the sense used in Problem 4.22 of [6] if and only if it is 1-connected-slice.) It is an open question whether every classical slice knot is ribbon. However in higher dimensions these notions are generally distinct. Every even-dimensional knot is slice, but a knot group is the group of a ribbon n-knot (for n ≥ 2) if and only if it has a Wirtinger presentation of deficiency 1 [11]. (More generally, if W is homotopy equivalent to a finite 2-complex and χ(W ) = 0 then def(π1(W )) ≥ 1.) There are n-knot groups with deficiency ≤ 0 for every n ≥ 2. In this note we shall show that every high-dimensional knot group π is the group of an (n−1)-connected-slice n-knot for all n ≥ 3. However the groups of n-connected-slice n-knots satisfy constraints related to 1991 Mathematics Subject Classification. 57Q45.
منابع مشابه
. G T / 0 50 52 33 v 1 1 2 M ay 2 00 5 NEW TOPOLOGICALLY SLICE KNOTS
In the early 1980’s Mike Freedman showed that all knots with trivial Alexander polynomial are topologically slice (with fundamental group Z). This paper contains the first new examples of topologically slice knots. In fact, we give a sufficient homological condition under which a knot is slice with fundamental group Z⋉Z[1/2]. These two fundamental groups are known to be the only solvable ribbon...
متن کاملNew topologically slice knots
In the early 1980’s Mike Freedman showed that all knots with trivial Alexander polynomial are topologically slice (with fundamental group Z). This paper contains the first new examples of topologically slice knots. In fact, we give a sufficient homological condition under which a knot is slice with fundamental group Z ⋉ Z[1/2]. These two fundamental groups are known to be the only solvable ribb...
متن کاملTim Cochran , Stefan Friedl And
which restricts to the given links at the ends. A link is called (topologically) slice if it is concordant to the trivial m–component link or, equivalently, if it bounds a flat embedding of m disjoint slice disks D2 ∐ · · · ∐D2 ֒→ D4. In the special case m = 1 we refer to the link as a knot. If the embeddings above are required to be C, or smooth, then these notions are called smoothly concordan...
متن کاملCovering Link Calculus and Iterated Bing Doubles
We give a new geometric obstruction to the iterated Bing double of a knot being a slice link: for n > 1 the (n + 1)st iterated Bing double of a knot is rationally slice if and only if the nth iterated Bing double of the knot is rationally slice. The main technique of the proof is a covering link construction simplifying a given link. We prove certain similar geometric obstructions for n ≤ 1 as ...
متن کاملSome Examples Related to Knot Sliceness
It is known that the linking form on the 2-cover of slice knots has a metabolizer. We show that several weaker conditions, or some other conditions related to sliceness, do not imply the existence of a metabolizer. We then show how the Rudolph-Bennequin inequality can be used indirectly to prove that some knots are not slice.
متن کامل